DLMF:31.14#Ex2 (Q9114)

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DLMF:31.14#Ex2
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    α β = j = 1 N a j q j . 𝛼 𝛽 superscript subscript 𝑗 1 𝑁 subscript 𝑎 𝑗 subscript 𝑞 𝑗 {\displaystyle{\displaystyle\alpha\beta=\sum_{j=1}^{N}a_{j}q_{j}.}}
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