DLMF:30.3#Ex4 (Q8832)

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DLMF:30.3#Ex4
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    α k = γ 2 ( k + 2 m + 1 ) ( k + 2 m + 2 ) ( 2 k + 2 m + 3 ) ( 2 k + 2 m + 5 ) , subscript 𝛼 𝑘 superscript 𝛾 2 𝑘 2 𝑚 1 𝑘 2 𝑚 2 2 𝑘 2 𝑚 3 2 𝑘 2 𝑚 5 {\displaystyle{\displaystyle\alpha_{k}=\gamma^{2}\frac{(k+2m+1)(k+2m+2)}{(2k+2% m+3)(2k+2m+5)},}}
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