DLMF:18.15#Ex2 (Q5699)

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DLMF:18.15#Ex2
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    θ B 0 ( θ ) = 1 4 g ( θ ) , 𝜃 subscript 𝐵 0 𝜃 1 4 𝑔 𝜃 {\displaystyle{\displaystyle\theta B_{0}(\theta)=\frac{1}{4}g(\theta),}}
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