DLMF:18.9#Ex3 (Q5598)

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DLMF:18.9#Ex3
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    C n = ( n + α ) ( n + β ) ( 2 n + α + β + 2 ) ( n + 1 ) ( n + α + β + 1 ) ( 2 n + α + β ) . subscript 𝐶 𝑛 𝑛 𝛼 𝑛 𝛽 2 𝑛 𝛼 𝛽 2 𝑛 1 𝑛 𝛼 𝛽 1 2 𝑛 𝛼 𝛽 {\displaystyle{\displaystyle C_{n}=\dfrac{(n+\alpha)(n+\beta)(2n+\alpha+\beta+% 2)}{(n+1)(n+\alpha+\beta+1)(2n+\alpha+\beta)}.}}
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