DLMF:14.15#Ex4 (Q4874)

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DLMF:14.15#Ex4
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    α = ( 2 | ν - μ + 1 2 | ν + 1 2 ) 1 / 2 , 𝛼 superscript 2 𝜈 𝜇 1 2 𝜈 1 2 1 2 {\displaystyle{\displaystyle\alpha=\left(\frac{2\left|\nu-\mu+\frac{1}{2}% \right|}{\nu+\frac{1}{2}}\right)^{1/2},}}
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