DLMF:13.7#Ex2 (Q4417)

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DLMF:13.7#Ex2
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    ν = ( 1 2 + 1 2 ⁢ 1 - 4 ⁢ σ 2 ) - 1 / 2 𝜈 superscript 1 2 1 2 1 4 superscript 𝜎 2 1 2 {\displaystyle{\displaystyle\nu=\left(\tfrac{1}{2}+\tfrac{1}{2}\sqrt{1-4\sigma% ^{2}}\right)^{-\ifrac{1}{2}}}}
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    DLMF:13.7#Ex2
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    Warning: Falling back to standard tex;
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