DLMF:12.14#Ex4 (Q4248)

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DLMF:12.14#Ex4
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    β n + 2 = a β n + 1 - 1 2 ( n + 1 ) ( 2 n + 3 ) β n , subscript 𝛽 𝑛 2 𝑎 subscript 𝛽 𝑛 1 1 2 𝑛 1 2 𝑛 3 subscript 𝛽 𝑛 {\displaystyle{\displaystyle\beta_{n+2}=a\beta_{n+1}-\tfrac{1}{2}(n+1)(2n+3)% \beta_{n},}}
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