DLMF:10.19#Ex25 (Q3244)

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DLMF:10.19#Ex25
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    R 3 ( a ) = 699 3500 a 6 - 2617 3150 a 3 + 23 3150 , subscript 𝑅 3 𝑎 699 3500 superscript 𝑎 6 2617 3150 superscript 𝑎 3 23 3150 {\displaystyle{\displaystyle R_{3}(a)=\tfrac{699}{3500}a^{6}-\tfrac{2617}{3150% }a^{3}+\tfrac{23}{3150},}}
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