DLMF:4.13.E9 (Q1650)

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DLMF:4.13.E9
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    1 3 5 ( 2 n + 1 ) c 2 n + 1 = g n , 1 3 5 2 𝑛 1 subscript 𝑐 2 𝑛 1 subscript 𝑔 𝑛 {\displaystyle{\displaystyle 1\cdot 3\cdot 5\cdots(2n+1)c_{2n+1}=g_{n},}}
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    Warning: Falling back to standard tex;
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    n 𝑛 {\displaystyle{\displaystyle n}}
    C4.S1.XMD3.m1cdec
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    c i subscript 𝑐 𝑖 {\displaystyle{\displaystyle c_{i}}}
    C4.S13.XMD1.m1cdec
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    g n subscript 𝑔 𝑛 {\displaystyle{\displaystyle g_{n}}}
    C4.S13.XMD2.m1dec
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