DLMF:3.10#Ex25 (Q1438)

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DLMF:3.10#Ex25
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    C 1 = C 0 + C 1 . subscript 𝐶 1 subscript 𝐶 0 subscript 𝐶 1 {\displaystyle{\displaystyle C_{1}=C_{0}+\nabla C_{1}.}}
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