DLMF:4.45.E8 (Q2014)

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DLMF:4.45.E8
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    Statements

    test
    2 ⁢ arctan ⁡ x 1 + ( 1 + x 2 ) 1 / 2 = arctan ⁡ x , 2 𝑥 1 superscript 1 superscript 𝑥 2 1 2 𝑥 {\displaystyle{\displaystyle 2\operatorname{arctan}\frac{x}{1+(1+x^{2})^{1/2}}% =\operatorname{arctan}x,}}
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    DLMF id
    DLMF:4.45.E8
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    constraint
    0 < x < ∞ 0 𝑥 {\displaystyle{\displaystyle 0<x<\infty}}
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