DLMF:4.35.E22 (Q1896)

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DLMF:4.35.E22
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    test
    tanh ⁡ z 2 = ( cosh ⁡ z - 1 cosh ⁡ z + 1 ) 1 / 2 = cosh ⁡ z - 1 sinh ⁡ z = sinh ⁡ z cosh ⁡ z + 1 . 𝑧 2 superscript 𝑧 1 𝑧 1 1 2 𝑧 1 𝑧 𝑧 𝑧 1 {\displaystyle{\displaystyle\tanh\frac{z}{2}=\left(\frac{\cosh z-1}{\cosh z+1}% \right)^{1/2}=\frac{\cosh z-1}{\sinh z}=\frac{\sinh z}{\cosh z+1}.}}
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    DLMF id
    DLMF:4.35.E22
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