DLMF:4.19.E9 (Q1688)

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DLMF:4.19.E9
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    Statements

    test
    ln ⁡ ( tan ⁡ z z ) = ∑ n = 1 ∞ ( - 1 ) n - 1 ⁢ 2 2 ⁢ n ⁢ ( 2 2 ⁢ n - 1 - 1 ) ⁢ B 2 ⁢ n n ⁢ ( 2 ⁢ n ) ! ⁢ z 2 ⁢ n , 𝑧 𝑧 superscript subscript 𝑛 1 superscript 1 𝑛 1 superscript 2 2 𝑛 superscript 2 2 𝑛 1 1 Bernoulli-number-B 2 𝑛 𝑛 2 𝑛 superscript 𝑧 2 𝑛 {\displaystyle{\displaystyle\ln\left(\frac{\tan z}{z}\right)=\sum_{n=1}^{% \infty}\frac{(-1)^{n-1}2^{2n}(2^{2n-1}-1)B_{2n}}{n(2n)!}z^{2n},}}
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    DLMF id
    DLMF:4.19.E9
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