Elliptic Integrals - 19.19 Taylor and Related Series

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19.19#Ex1 A = 1 n ⁒ βˆ‘ j = 1 n z j 𝐴 1 𝑛 superscript subscript 𝑗 1 𝑛 subscript 𝑧 𝑗 {\displaystyle{\displaystyle A=\frac{1}{n}\sum_{j=1}^{n}z_{j}}}
A = \frac{1}{n}\sum_{j=1}^{n}z_{j}

A = (1)/(n)*sum(z[j], j = 1..n)
A == Divide[1,n]*Sum[Subscript[z, j], {j, 1, n}, GenerateConditions->None]
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19.19#Ex2 Z j = 1 - ( z j / A ) subscript 𝑍 𝑗 1 subscript 𝑧 𝑗 𝐴 {\displaystyle{\displaystyle Z_{j}=1-(z_{j}/A)}}
Z_{j} = 1-(z_{j}/A)

Z[j] = 1 -(z[j]/A)
Subscript[Z, j] == 1 -(Subscript[z, j]/A)
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19.19#Ex3 E 1 ⁒ ( 𝐙 ) = 0 subscript 𝐸 1 𝐙 0 {\displaystyle{\displaystyle E_{1}(\mathbf{Z})=0}}
E_{1}(\mathbf{Z}) = 0
| Z j | < 1 subscript 𝑍 𝑗 1 {\displaystyle{\displaystyle|Z_{j}|<1}}
E[1](Z) = 0
Subscript[E, 1][Z] == 0
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