DLMF:3.5#Ex11 (Q1269)

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DLMF:3.5#Ex11
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    γ n = π 2 2 n + 1 , subscript 𝛾 𝑛 superscript 2 2 𝑛 1 {\displaystyle{\displaystyle\gamma_{n}=\frac{\pi}{2^{2n+1}},}}
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    α = β = 1 2 𝛼 𝛽 1 2 {\displaystyle{\displaystyle\alpha=\beta=\tfrac{1}{2}}}
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