DLMF:28.26.E3 (Q8419)

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DLMF:28.26.E3
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    test
    ϕ = 2 ⁢ h ⁢ sinh ⁡ z - ( m + 1 2 ) ⁢ arctan ⁡ ( sinh ⁡ z ) . italic-ϕ 2 ℎ 𝑧 𝑚 1 2 𝑧 {\displaystyle{\displaystyle\phi=2h\sinh z-\left(m+\tfrac{1}{2}\right)% \operatorname{arctan}\left(\sinh z\right).}}
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    DLMF:28.26.E3
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