DLMF:23.22.E3 (Q7390)

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DLMF:23.22.E3
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    2 ω 1 = 2 e - π i / 3 ω 3 = ( Γ ( 1 3 ) ) 3 2 π d 1 / 6 . 2 subscript 𝜔 1 2 superscript 𝑒 𝜋 𝑖 3 subscript 𝜔 3 superscript Euler-Gamma 1 3 3 2 𝜋 superscript 𝑑 1 6 {\displaystyle{\displaystyle 2\omega_{1}=2e^{-\pi i/3}\omega_{3}=\frac{\left(% \Gamma\left(\frac{1}{3}\right)\right)^{3}}{2\pi d^{1/6}}.}}
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