DLMF:18.15#Ex3 (Q5700)

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DLMF:18.15#Ex3
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    A 1 ( θ ) = 1 8 g ( θ ) - 1 + 2 α 8 g ( θ ) θ - 1 32 ( g ( θ ) ) 2 , subscript 𝐴 1 𝜃 1 8 superscript 𝑔 𝜃 1 2 𝛼 8 𝑔 𝜃 𝜃 1 32 superscript 𝑔 𝜃 2 {\displaystyle{\displaystyle A_{1}(\theta)=\frac{1}{8}g^{\prime}(\theta)-\frac% {1+2\alpha}{8}\frac{g(\theta)}{\theta}-\frac{1}{32}(g(\theta))^{2},}}
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    Warning: Falling back to standard tex;
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