DLMF:16.3.E6 (Q5193)

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DLMF:16.3.E6
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    test
    z ⁢ F 1 0 ⁡ ( - ; b + 1 ; z ) + b ⁢ ( b - 1 ) ⁢ F 1 0 ⁡ ( - ; b ; z ) - b ⁢ ( b - 1 ) ⁢ F 1 0 ⁡ ( - ; b - 1 ; z ) = 0 , 𝑧 Gauss-hypergeometric-pFq 0 1 𝑏 1 𝑧 𝑏 𝑏 1 Gauss-hypergeometric-pFq 0 1 𝑏 𝑧 𝑏 𝑏 1 Gauss-hypergeometric-pFq 0 1 𝑏 1 𝑧 0 {\displaystyle{\displaystyle z{{}_{0}F_{1}}\left(-;b+1;z\right)+b(b-1){{}_{0}F% _{1}}\left(-;b;z\right)-b(b-1){{}_{0}F_{1}}\left(-;b-1;z\right)=0,}}
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    DLMF:16.3.E6
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