DLMF:15.12.E8 (Q5168)

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DLMF:15.12.E8
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    test
    α = ( - 2 ⁢ ln ⁡ ( 1 - ( z - 1 z + 1 ) 2 ) ) 1 / 2 , 𝛼 superscript 2 1 superscript 𝑧 1 𝑧 1 2 1 2 {\displaystyle{\displaystyle\alpha=\left(-2\ln\left(1-\left(\frac{z-1}{z+1}% \right)^{2}\right)\right)^{1/2},}}
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    DLMF:15.12.E8
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