DLMF:13.7#Ex6 (Q4421)

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DLMF:13.7#Ex6
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    ρ = 1 2 | 2 a 2 - 2 a b + b | + σ ( 1 + 1 4 σ ) ( 1 - σ ) 2 𝜌 1 2 2 superscript 𝑎 2 2 𝑎 𝑏 𝑏 𝜎 1 1 4 𝜎 superscript 1 𝜎 2 {\displaystyle{\displaystyle\rho=\tfrac{1}{2}\left|2a^{2}-2ab+b\right|+\frac{% \sigma(1+\frac{1}{4}\sigma)}{(1-\sigma)^{2}}}}
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    Warning: Falling back to standard tex;
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