DLMF:1.6.E2 (Q173)

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DLMF:1.6.E2
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    𝐚 𝐛 = a 1 b 1 + a 2 b 2 + a 3 b 3 . 𝐚 𝐛 subscript 𝑎 1 subscript 𝑏 1 subscript 𝑎 2 subscript 𝑏 2 subscript 𝑎 3 subscript 𝑏 3 {\displaystyle{\displaystyle\mathbf{a}\cdot\mathbf{b}=a_{1}b_{1}+a_{2}b_{2}+a_% {3}b_{3}.}}
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    Warning: Falling back to standard tex;
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