DLMF:36.13.E5 (Q10013)

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DLMF:36.13.E5
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    test
    | ϕ | = ϕ c = arcsin ⁡ ( 1 3 ) = 19 ∘ ⁢ .47122 . italic-ϕ subscript italic-ϕ 𝑐 1 3 superscript 19 .47122 {\displaystyle{\displaystyle|\phi|=\phi_{c}=\operatorname{arcsin}\left(\tfrac{% 1}{3}\right)=19^{\circ}.47122.}}
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    DLMF:36.13.E5
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