DLMF:16.4.E2 (Q5196)

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DLMF:16.4.E2
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    a 1 + + a q + 1 + k = b 1 + + b q . subscript 𝑎 1 subscript 𝑎 𝑞 1 𝑘 subscript 𝑏 1 subscript 𝑏 𝑞 {\displaystyle{\displaystyle a_{1}+\dots+a_{q+1}+k=b_{1}+\dots+b_{q}.}}
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    Warning: Falling back to standard tex;
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