DLMF:14.12.E10 (Q4831)

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DLMF:14.12.E10
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    test
    u = 1 2 ⁢ ln ⁡ ( x + 1 x - 1 ) . 𝑢 1 2 𝑥 1 𝑥 1 {\displaystyle{\displaystyle u=\frac{1}{2}\ln\left(\frac{x+1}{x-1}\right).}}
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    DLMF:14.12.E10
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