DLMF:1.3.E3 (Q63)

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DLMF:1.3.E3
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    A j k = ( - 1 ) j + k M j k . subscript 𝐴 𝑗 𝑘 superscript 1 𝑗 𝑘 subscript 𝑀 𝑗 𝑘 {\displaystyle{\displaystyle A_{jk}=(-1)^{j+k}M_{jk}.}}
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    Warning: Falling back to standard tex;
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