DLMF:1.2.E10} (Q39)

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DLMF:1.2.E10}
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    a + ( a + d ) + ( a + 2 d ) + + ( a + ( n - 1 ) d ) = n a + 1 2 n ( n - 1 ) d = 1 2 n ( a + ) , 𝑎 𝑎 𝑑 𝑎 2 𝑑 𝑎 𝑛 1 𝑑 𝑛 𝑎 1 2 𝑛 𝑛 1 𝑑 1 2 𝑛 𝑎 {\displaystyle{\displaystyle a+(a+d)+(a+2d)+\dots+(a+(n-1)d)=na+\tfrac{1}{2}n(% n-1)d=\tfrac{1}{2}n(a+\ell),}}
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    Warning: Falling back to standard tex;
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