DLMF:10.20.E10 (Q3259)

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DLMF:10.20.E10
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    A k ( ζ ) = j = 0 2 k ( 3 2 ) j v j ζ - 3 j / 2 U 2 k - j ( ( 1 - z 2 ) - 1 2 ) , subscript 𝐴 𝑘 𝜁 superscript subscript 𝑗 0 2 𝑘 superscript 3 2 𝑗 subscript 𝑣 𝑗 superscript 𝜁 3 𝑗 2 subscript 𝑈 2 𝑘 𝑗 superscript 1 superscript 𝑧 2 1 2 {\displaystyle{\displaystyle A_{k}(\zeta)=\sum_{j=0}^{2k}(\tfrac{3}{2})^{j}v_{% j}\zeta^{-3j/2}U_{2k-j}\left((1-z^{2})^{-\frac{1}{2}}\right),}}
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    Warning: Falling back to standard tex;
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    k 𝑘 {\displaystyle{\displaystyle k}}
    C10.S1.XMD3.m1fdec
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